If bar{a}, bar{b}, bar{c}, bar{d} are the pos | vedclass

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(B) Given the equation $3 \bar{a}-\bar{b}+2 \bar{c}-4 \bar{d}=\overline{0}$.Rearranging the terms,we get $3 \bar{a}+2 \bar{c}=\bar{b}+4 \bar{d}$.Divid

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$\frac{3 \bar{a}+2 \bar{c}}{5}$

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(B) Given the equation $3 \bar{a}-\bar{b}+2 \bar{c}-4 \bar{d}=\overline{0}$.Rearranging the terms,we get $3 \bar{a}+2 \bar{c}=\bar{b}+4 \bar{d}$.Dividing both sides by $5$,we have $\frac{3 \bar{a}+2 \bar{c}}{5}=\frac{\bar{b}+4 \bar{d}}{5}$.Let $\bar{r} = \frac{3 \bar{a}+2 \bar{c}}{3+2} = \frac{\bar{b}+4 \bar{d}}{1+4}$.This vector $\bar{r}$ represents a point that lies on the line segment $AC$ (dividing it in ratio $2:3$) and also on the line segment $BD$ (dividing it in ratio $4:1$).Thus,$\bar{r}$ is the position vector of the point of intersection of $AC$ and $BD$.

If $\bar{a}, \bar{b}, \bar{c}, \bar{d}$ are the position vectors of the points $A, B, C, D$ respectively such that $3 \bar{a}-\bar{b}+2 \bar{c}-4 \bar{d}=\overline{0}$,then the position vector of the point of intersection of the line segments $AC$ and $BD$ is

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