If $\bar{a}, \bar{b}, \bar{c}$ are perpendicular to $\bar{b}+\bar{c}, \bar{c}+\bar{a}$ and $\bar{a}+\bar{b}$ respectively and $|\bar{a}+\bar{b}|=2, |\bar{b}+\bar{c}|=6, |\bar{c}+\bar{a}|=4$,then $|\bar{a}+\bar{b}+\bar{c}|=$

  • A
    $2 \sqrt{6}$
  • B
    $2 \sqrt{7}$
  • C
    $3 \sqrt{6}$
  • D
    $3 \sqrt{7}$

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