यदि A = begin{bmatrix} 1 & -2 3 & 0 end{bmat | vedclass

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(B) दिया गया है $A = \begin{bmatrix} 1 & -2 \ 3 & 0 \end{bmatrix}$,$B = \begin{bmatrix} -1 & 4 \ 2 & 3 \end{bmatrix}$,और $C = \begin{bmatrix} 0 & -1

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$\begin{bmatrix} 8 & -20 \ 7 & -9 \end{bmatrix}$

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(B) दिया गया है $A = \begin{bmatrix} 1 & -2 \ 3 & 0 \end{bmatrix}$,$B = \begin{bmatrix} -1 & 4 \ 2 & 3 \end{bmatrix}$,और $C = \begin{bmatrix} 0 & -1 \ 1 & 0 \end{bmatrix}$.हमें $5A - 3B - 2C$ की गणना करनी है।सबसे पहले,अदिश गुणन (scalar multiplication) ज्ञात करें:$5A = 5 \begin{bmatrix} 1 & -2 \ 3 & 0 \end{bmatrix} = \begin{bmatrix} 5 & -10 \ 15 & 0 \end{bmatrix}$$3B = 3 \begin{bmatrix} -1 & 4 \ 2 & 3 \end{bmatrix} = \begin{bmatrix} -3 & 12 \ 6 & 9 \end{bmatrix}$$2C = 2 \begin{bmatrix} 0 & -1 \ 1 & 0 \end{bmatrix} = \begin{bmatrix} 0 & -2 \ 2 & 0 \end{bmatrix}$अब,आव्यूह का घटाव करें:$5A - 3B - 2C = \begin{bmatrix} 5 & -10 \ 15 & 0 \end{bmatrix} - \begin{bmatrix} -3 & 12 \ 6 & 9 \end{bmatrix} - \begin{bmatrix} 0 & -2 \ 2 & 0 \end{bmatrix}$$= \begin{bmatrix} 5 - (-3) - 0 & -10 - 12 - (-2) \ 15 - 6 - 2 & 0 - 9 - 0 \end{bmatrix}$$= \begin{bmatrix} 5 + 3 & -22 + 2 \ 7 & -9 \end{bmatrix}$$= \begin{bmatrix} 8 & -20 \ 7 & -9 \end{bmatrix}$.

यदि $A = \begin{bmatrix} 1 & -2 \\ 3 & 0 \end{bmatrix}$,$B = \begin{bmatrix} -1 & 4 \\ 2 & 3 \end{bmatrix}$,$C = \begin{bmatrix} 0 & -1 \\ 1 & 0 \end{bmatrix}$ है,तो $5A - 3B - 2C = $

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