If A = begin{bmatrix} 1 & 0 2 & 0 end{bmatri | vedclass

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(B) First,calculate the product $AB$: $AB = \begin{bmatrix} 1 & 0 \ 2 & 0 \end{bmatrix} \begin{bmatrix} 0 & 0 \ 1 & 12 \end{bmatrix} = \begin{bmatri

Vedclass · Accepted Answer

$AB = O, BA 
eq O$

Vedclass · Answer

(B) First,calculate the product $AB$: $AB = \begin{bmatrix} 1 & 0 \ 2 & 0 \end{bmatrix} \begin{bmatrix} 0 & 0 \ 1 & 12 \end{bmatrix} = \begin{bmatrix} (1)(0) + (0)(1) & (1)(0) + (0)(12) \ (2)(0) + (0)(1) & (2)(0) + (0)(12) \end{bmatrix} = \begin{bmatrix} 0 & 0 \ 0 & 0 \end{bmatrix} = O$. Next,calculate the product $BA$: $BA = \begin{bmatrix} 0 & 0 \ 1 & 12 \end{bmatrix} \begin{bmatrix} 1 & 0 \ 2 & 0 \end{bmatrix} = \begin{bmatrix} (0)(1) + (0)(2) & (0)(0) + (0)(0) \ (1)(1) + (12)(2) & (1)(0) + (12)(0) \end{bmatrix} = \begin{bmatrix} 0 & 0 \ 25 & 0 \end{bmatrix} 
eq O$. Thus,$AB = O$ and $BA 
eq O$.

If $A = \begin{bmatrix} 1 & 0 \\ 2 & 0 \end{bmatrix}$ and $B = \begin{bmatrix} 0 & 0 \\ 1 & 12 \end{bmatrix}$,then:

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