If A = begin{bmatrix} 1 & 2 0 & 1 end{bmatri | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given $A = \begin{bmatrix} 1 & 2 \ 0 & 1 \end{bmatrix}$.Calculate ${A^2} = A 	imes A = \begin{bmatrix} 1 & 2 \ 0 & 1 \end{bmatrix} \begin{bmatr

Vedclass · Accepted Answer

$\begin{bmatrix} 1 & 2n \ 0 & 1 \end{bmatrix}$

Vedclass · Answer

(A) Given $A = \begin{bmatrix} 1 & 2 \ 0 & 1 \end{bmatrix}$.Calculate ${A^2} = A 	imes A = \begin{bmatrix} 1 & 2 \ 0 & 1 \end{bmatrix} \begin{bmatrix} 1 & 2 \ 0 & 1 \end{bmatrix} = \begin{bmatrix} 1(1)+2(0) & 1(2)+2(1) \ 0(1)+1(0) & 0(2)+1(1) \end{bmatrix} = \begin{bmatrix} 1 & 4 \ 0 & 1 \end{bmatrix}$.Calculate ${A^3} = {A^2} 	imes A = \begin{bmatrix} 1 & 4 \ 0 & 1 \end{bmatrix} \begin{bmatrix} 1 & 2 \ 0 & 1 \end{bmatrix} = \begin{bmatrix} 1(1)+4(0) & 1(2)+4(1) \ 0(1)+1(0) & 0(2)+1(1) \end{bmatrix} = \begin{bmatrix} 1 & 6 \ 0 & 1 \end{bmatrix}$.Observing the pattern,we see that for any positive integer $n$,the matrix follows the form ${A^n} = \begin{bmatrix} 1 & 2n \ 0 & 1 \end{bmatrix}$.Thus,the correct option is $A$.

If $A = \begin{bmatrix} 1 & 2 \\ 0 & 1 \end{bmatrix}$,then ${A^n} = $

Similar Questions

Let $A = \begin{bmatrix} 2 & -2 \\ 1 & -1 \end{bmatrix}$ and $B = \begin{bmatrix} -1 & 2 \\ -1 & 2 \end{bmatrix}$. Then the number of elements in the set $\{(n, m) : n, m \in \{1, 2, \ldots, 10\} \text{ and } nA^n + mB^m = I\}$ is

If $A = \begin{bmatrix} 3 & -2 \\ 4 & -2 \end{bmatrix}$ and $I = \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}$,find $k$ such that $A^{2} = kA - 2I$.

If $M = \begin{bmatrix} 1 & 2 \\ 2 & 3 \end{bmatrix}$ and $M^2 - \lambda M - I_2 = 0$,then $\lambda = $

Find $X$ and $Y$,if $X+Y=\left[\begin{array}{ll}5 & 2 \\ 0 & 9\end{array}\right]$ and $X-Y=\left[\begin{array}{cc}3 & 6 \\ 0 & -1\end{array}\right]$.

If $P = \begin{bmatrix} \cos \frac{\pi}{4} & -\sin \frac{\pi}{4} \\ \sin \frac{\pi}{4} & \cos \frac{\pi}{4} \end{bmatrix}$ and $X = \begin{bmatrix} \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{2}} \end{bmatrix}$, then $P^3 X$ is equal to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module