If A = begin{bmatrix} 1 & -1 2 & 3 end{bmatr | vedclass

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(B) For a $2 	imes 2$ matrix $A = \begin{bmatrix} a & b \ c & d \end{bmatrix}$,the adjoint of $A$ is given by $	ext{adj } A = \begin{bmatrix} d & -

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$\begin{bmatrix} 3 & 1 \ -2 & 1 \end{bmatrix}$

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(B) For a $2 	imes 2$ matrix $A = \begin{bmatrix} a & b \ c & d \end{bmatrix}$,the adjoint of $A$ is given by $	ext{adj } A = \begin{bmatrix} d & -b \ -c & a \end{bmatrix}$.Given $A = \begin{bmatrix} 1 & -1 \ 2 & 3 \end{bmatrix}$,we have $a = 1, b = -1, c = 2, d = 3$.Substituting these values into the formula:$	ext{adj } A = \begin{bmatrix} 3 & -(-1) \ -2 & 1 \end{bmatrix} = \begin{bmatrix} 3 & 1 \ -2 & 1 \end{bmatrix}$.Thus,the correct option is $B$.

If $A = \begin{bmatrix} 1 & -1 \\ 2 & 3 \end{bmatrix}$,then $\text{adj } A$ is equal to

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