Class 11MathematicsTrigonometrical Ratios, Functions and IdentitiesMix Examples-Trigonometrical Ratios, Functions and Identities
EasyIf $(1 + \sin A)(1 + \sin B)(1 + \sin C) = (1 - \sin A)(1 - \sin B)(1 - \sin C)$,then each side is equal to
- A$\pm \sin A \sin B \sin C$
- B$\pm \cos A \cos B \cos C$
- C$\pm \sin A \cos B \cos C$
- D$\pm \cos A \sin B \sin C$
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Evaluate: $\cos \frac{\pi}{7} \cos \frac{2 \pi}{7} \cos \frac{3 \pi}{7} \cos \frac{\pi}{14} \cos \frac{3 \pi}{14} \cos \frac{5 \pi}{14}$
If $A = \frac{\sin 3^\circ}{\cos 9^\circ} + \frac{\sin 9^\circ}{\cos 27^\circ} + \frac{\sin 27^\circ}{\cos 81^\circ}$ and $B = \tan 81^\circ - \tan 3^\circ$, then $\frac{B}{A}$ is equal to . . . . . . .
DifficultJEE MAIN 2026
View SolutionIf $\tan A$ and $\tan B$ are the roots of the quadratic equation $x^2-px+q=0$,then $\sin^2(A+B)$ is equal to
DifficultAP EAMCET 2011
View SolutionIf $\cos x+\cos y+\cos \alpha=0$ and $\sin x+\sin y+\sin \alpha=0$,then $\cot \left(\frac{x+y}{2}\right)$ is equal to
$\tan 81^{\circ}-\tan 63^{\circ}-\tan 27^{\circ}+\tan 9^{\circ}$ equals to
DifficultTS EAMCET 2014
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