If $\sin (\theta + \alpha ) = a$ and $\sin (\theta + \beta ) = b,$ then $\cos 2(\alpha - \beta ) - 4ab\cos (\alpha - \beta )$ is equal to

  • A
    $1 - a^2 - b^2$
  • B
    $1 - 2a^2 - 2b^2$
  • C
    $2 + a^2 + b^2$
  • D
    $2 - a^2 - b^2$

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