If E. coli was allowed to grow for 60 minutes | vedclass

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(B) In the Meselson and Stahl experiment,$E. coli$ divides every $20$ minutes. Starting with one heavy $(^{15}N^{15}N)$ $DNA$ molecule: After $20$ min

Vedclass · Accepted Answer

$3: 1$

Vedclass · Answer

(B) In the Meselson and Stahl experiment,$E. coli$ divides every $20$ minutes. Starting with one heavy $(^{15}N^{15}N)$ $DNA$ molecule: After $20$ minutes (first generation): $2$ hybrid $(^{15}N^{14}N)$ $DNA$ molecules are formed. After $40$ minutes (second generation): $2$ hybrid $(^{15}N^{14}N)$ and $2$ light $(^{14}N^{14}N)$ $DNA$ molecules are formed. After $60$ minutes (third generation): The $2$ hybrid molecules produce $2$ hybrid and $2$ light molecules,and the $2$ light molecules produce $4$ light molecules. Total $DNA$ molecules = $8$. Number of hybrid molecules = $2$. Number of light molecules = $6$. Ratio of light to hybrid = $6: 2$,which simplifies to $3: 1$.

If $E. coli$ was allowed to grow for $60$ minutes,then what would be the respective proportions of light and hybrid density $DNA$ molecules?

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