If $A$ lies in the third quadrant and $3 \tan A - 4 = 0,$ then $5 \sin 2A + 3 \sin A + 4 \cos A = $

  • A
    $0$
  • B
    $\frac{-24}{5}$
  • C
    $\frac{24}{5}$
  • D
    $\frac{48}{5}$

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