If $1, \omega, \omega^{2}$ are the cube roots of unity,then $(1+\omega)(1+\omega^{2})(1+\omega^{4})(1+\omega^{8})$ is equal to
- A$1$
- B$0$
- C$\omega^{2}$
- D$\omega$
Explore More
Similar Questions
If $1, \omega, \omega^2$ denote the cube roots of unity,then the value of $(1-\omega+\omega^2)^5+(1+\omega-\omega^2)^5$ is
If $\omega$ is an imaginary cube root of unity,then the value of $\sin \left[ (\omega^{10} + \omega^{23})\pi - \frac{\pi}{4} \right]$ is
MediumIIT 1994
View SolutionIf $n$ is an integer which leaves a remainder of $1$ when divided by $3$,then $(1+\sqrt{3}i)^n + (1-\sqrt{3}i)^n$ equals
DifficultTS EAMCET 2009
View SolutionIn the Argand plane,no value of $\sqrt[3]{1-i \sqrt{3}}$ lies in which quadrant?
If $\omega$ is a complex cube root of unity,then $(1 + \omega - \omega^2)(1 - \omega + \omega^2) = $
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo