If p(frac{1}{q}+frac{1}{r}), q(frac{1}{r}+fra | vedclass

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(B) Given terms are in $AP$: $p(\frac{q+r}{qr}), q(\frac{p+r}{pr}), r(\frac{p+q}{pq})$.Adding $1$ to each term,the sequence remains in $AP$:$\frac{pq+

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are in $AP$

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(B) Given terms are in $AP$: $p(\frac{q+r}{qr}), q(\frac{p+r}{pr}), r(\frac{p+q}{pq})$.Adding $1$ to each term,the sequence remains in $AP$:$\frac{pq+pr+qr}{qr}, \frac{qp+qr+pr}{pr}, \frac{rp+rq+pq}{pq}$ are in $AP$.Let $S = pq+pr+qr$. Then $\frac{S}{qr}, \frac{S}{pr}, \frac{S}{pq}$ are in $AP$.Dividing each term by $S$ (assuming $S 
eq 0$),we get $\frac{1}{qr}, \frac{1}{pr}, \frac{1}{pq}$ are in $AP$.Multiplying each term by $pqr$,we get $p, q, r$ are in $AP$.

If $p(\frac{1}{q}+\frac{1}{r}), q(\frac{1}{r}+\frac{1}{p}), r(\frac{1}{p}+\frac{1}{q})$ are in $AP$,then $p, q, r$:

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