If A and B are two non-mutually exclusive eve | vedclass

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(D) Given that $A$ and $B$ are non-mutually exclusive events,we have $P(A \cap B) 
eq 0$. Given the condition $P(A \mid B) = P(B \mid A)$. Using the

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$P(A) = P(B)$

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(D) Given that $A$ and $B$ are non-mutually exclusive events,we have $P(A \cap B) 
eq 0$. Given the condition $P(A \mid B) = P(B \mid A)$. Using the definition of conditional probability,we have: $\frac{P(A \cap B)}{P(B)} = \frac{P(B \cap A)}{P(A)}$ Since $P(A \cap B) = P(B \cap A)$,we can divide both sides by $P(A \cap B)$ because $P(A \cap B) 
eq 0$: $\frac{1}{P(B)} = \frac{1}{P(A)}$ Therefore,$P(A) = P(B)$.

If $A$ and $B$ are two non-mutually exclusive events such that $P(A \mid B) = P(B \mid A)$,then

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