(D) Given $b = 3, c = 4$ and $B = \frac{\pi}{3}$.We calculate $c \sin B = 4 \sin \frac{\pi}{3} = 4 \times \frac{\sqrt{3}}{2} = 2\sqrt{3}$.Since $\sqrt

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(D) Given $b = 3, c = 4$ and $B = \frac{\pi}{3}$.We calculate $c \sin B = 4 \sin \frac{\pi}{3} = 4 \times \frac{\sqrt{3}}{2} = 2\sqrt{3}$.Since $\sqrt{3} \approx 1.732$,we have $2\sqrt{3} \approx 3.464$.Comparing this with $b$,we find $c \sin B = 2\sqrt{3} > 3 = b$.Since $b Therefore,no triangle can be constructed.

Class 11 Mathematics Trigonometrical Equations Relation between sides and angles, Solutions of triangles

Medium

If $b = 3, c = 4$ and $B = \frac{\pi}{3}$,then the number of triangles that can be constructed is

A
Infinite
B
Two
C
One
D
Nil

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Class 11

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Trigonometrical Equations

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Relation between sides and angles, Solutions of triangles

In $\triangle ABC$, with usual notations, $(a + b + c)(b + c - a)(c + a - b)(a + b - c) = 3b^2c^2$, then $\angle A = $

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In $\Delta ABC$,if $\sin^{2} A + \sin^{2} B + \sin^{2} C = 2$,then the triangle is:

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In a $\triangle ABC$,$\cot A+\cot B+\cot C=$

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The area of triangle $ABC$,in which $a = 1$,$b = 2$,and $\angle C = 60^\circ$ is

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If $\tan \frac{B - C}{2} = x \cot \frac{A}{2},$ then $x = $

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If $b = 3, c = 4$ and $B = \frac{\pi}{3}$,then the number of triangles that can be constructed is

Similar Questions

In $\triangle ABC$, with usual notations, $(a + b + c)(b + c - a)(c + a - b)(a + b - c) = 3b^2c^2$, then $\angle A = $

In $\Delta ABC$,if $\sin^{2} A + \sin^{2} B + \sin^{2} C = 2$,then the triangle is:

In a $\triangle ABC$,$\cot A+\cot B+\cot C=$

The area of triangle $ABC$,in which $a = 1$,$b = 2$,and $\angle C = 60^\circ$ is

If $\tan \frac{B - C}{2} = x \cot \frac{A}{2},$ then $x = $

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