If 5 A of current is passed for 193 s throu | vedclass

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(A) The total charge $Q$ passed through the solution is given by $Q = I 	imes t = 5 \ A 	imes 193 \ s = 965 \ C$. According to Faraday's law of elec

Vedclass · Accepted Answer

$+2$

Vedclass · Answer

(A) The total charge $Q$ passed through the solution is given by $Q = I 	imes t = 5 \ A 	imes 193 \ s = 965 \ C$. According to Faraday's law of electrolysis,the mass deposited $m = \frac{M 	imes Q}{n 	imes F}$,where $M$ is the molar mass of $Cu$ $(63.5 \ g/mol)$,$n$ is the oxidation state (valency),and $F$ is Faraday's constant $(96500 \ C/mol)$. Substituting the values: $0.32 = \frac{63.5 	imes 965}{n 	imes 96500}$. $0.32 = \frac{63.5}{100 	imes n}$. $n = \frac{63.5}{32} \approx 1.98 \approx 2$. Therefore,the oxidation state of $Cu$ in the salt is $+2$.

If $5 \ A$ of current is passed for $193 \ s$ through a solution containing $Cu$ salt,$0.32 \ g$ of copper is deposited. What is the oxidation state of the $Cu$ in the salt?

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