If $\alpha_1, \alpha_2, \alpha_3$ respectively denote the moduli of the complex numbers $-i, \frac{1}{3}(1+i)$ and $-1+i$,then their increasing order is
- A$\alpha_1, \alpha_2, \alpha_3$
- B$\alpha_3, \alpha_2, \alpha_1$
- C$\alpha_2, \alpha_1, \alpha_3$
- D$\alpha_3, \alpha_1, \alpha_2$
Explore More
Similar Questions
The complex number $\frac{1+2i}{1-i}$ lies in
The number of integer solutions of the equation $|1-i|^x=2^x$ is
DifficultAP EAMCET 2022
View SolutionThe real part of $(1 - \cos \theta + 2i\sin \theta )^{-1}$ is
MediumIIT 1986
View SolutionLet $\alpha$ be a fixed non-zero complex number with $|\alpha| < 1$ and $w = \frac{z-\alpha}{1-\bar{\alpha}z}$,where $z$ is a complex number. Then,
If $z \neq 0$ is a complex number such that $|z - \frac{1}{z}| = 2$,then the maximum value of $|z|$ is:
DifficultJEE MAIN 2022
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo