If sin(270^{circ}-x^{circ})=cos 292^{circ},th | vedclass

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(D) Given the equation: $\sin(270^{\circ}-x^{\circ})=\cos 292^{\circ}$.Using the allied angle formula $\sin(270^{\circ}-	heta) = -\cos 	heta$,we hav

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$112$

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(D) Given the equation: $\sin(270^{\circ}-x^{\circ})=\cos 292^{\circ}$.Using the allied angle formula $\sin(270^{\circ}-	heta) = -\cos 	heta$,we have:$-\cos x^{\circ} = \cos 292^{\circ}$.Since $\cos(180^{\circ}-	heta) = -\cos 	heta$,we can write:$-\cos x^{\circ} = \cos(180^{\circ}-112^{\circ}) = \cos 68^{\circ}$.Alternatively,using $-\cos 	heta = \cos(180^{\circ}+	heta)$:$-\cos x^{\circ} = \cos(180^{\circ}+x^{\circ})$.Comparing $\cos(180^{\circ}+x^{\circ}) = \cos 292^{\circ}$,we get:$180+x = 292 \implies x = 292-180 = 112$.Thus,$x = 112$.

If $\sin(270^{\circ}-x^{\circ})=\cos 292^{\circ}$,then a value of $x$ is

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