If $\sin x \cosh y = \cos \theta$,$\cos x \sinh y = \sin \theta$ and $4 \tan x = 3$,then $\sinh^2 y =$

  • A
    $\frac{4}{5}$
  • B
    $\frac{9}{16}$
  • C
    $\frac{9}{25}$
  • D
    $\frac{16}{25}$

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