If f: N rightarrow Z is defined by f(n)=begin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given the function $f(n)$ defined as:$f(n) = \begin{cases} 2 & 	ext{if } n=3k, k \in Z \ 10 & 	ext{if } n=3k+1, k \in Z \ 0 & 	ext{if } n=3k+

Vedclass · Accepted Answer

$\{1, 4, 7, \dots\}$

Vedclass · Answer

(B) Given the function $f(n)$ defined as:$f(n) = \begin{cases} 2 & 	ext{if } n=3k, k \in Z \ 10 & 	ext{if } n=3k+1, k \in Z \ 0 & 	ext{if } n=3k+2, k \in Z \end{cases}$We want to find the set $\{n \in N: f(n) > 2\}$.Looking at the definition,$f(n) > 2$ only when $f(n) = 10$,which occurs when $n = 3k + 1$ for some $k \in Z$.Since $n \in N$ (natural numbers),we consider $k \geq 0$ (assuming $N = \{1, 2, 3, \dots\}$):For $k=0, n = 3(0) + 1 = 1$.For $k=1, n = 3(1) + 1 = 4$.For $k=2, n = 3(2) + 1 = 7$.Thus,the set is $\{1, 4, 7, \dots\}$.

If $f: N \rightarrow Z$ is defined by $f(n)=\begin{cases} 2 & \text{if } n=3k, k \in Z \\ 10 & \text{if } n=3k+1, k \in Z \\ 0 & \text{if } n=3k+2, k \in Z \end{cases}$,then $\{n \in N: f(n)>2\}$ is equal to

Similar Questions

Which combination of tissues acts together to provide support to the hypocotyl of a seedling?

$A$ man slides down a telegraphic pole with an acceleration equal to one-fourth of the acceleration due to gravity. The frictional force between the man and the pole is equal to which of the following in terms of the man's weight $w$?

In which of the following plants can hybrid embryos be obtained?

Which type of chromosome is shown in the figure below?

The solution of $\frac{dy}{dx} = \frac{x \log x^2 + x}{\sin y + y \cos y}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module