If $f(x)=\begin{cases} \frac{2 x e^{\frac{1}{2 x}}-3 x e^{\frac{-1}{2 x}}}{e^{\frac{1}{2 x}}+4 e^{\frac{-1}{2 x}}} & \text{if } x \neq 0 \\ 0 & \text{if } x=0 \end{cases}$ is a real valued function,then:

  • A
    $f^{\prime}(0^{+}) = -\frac{3}{4}$
  • B
    $f^{\prime}(0^{-}) = 2$
  • C
    $f$ is not differentiable at $x=0$
  • D
    $f$ is differentiable at $x=0$

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