If 2 x^2-3 x y+y^2+x+2 y-8=0,then frac{d y}{d | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given the equation: $2 x^2-3 x y+y^2+x+2 y-8=0$Differentiating both sides with respect to $x$ using the chain rule and product rule:$\frac{d}{d x}

Vedclass · Accepted Answer

$\frac{3 y-4 x-1}{2 y-3 x+2}$

Vedclass · Answer

(A) Given the equation: $2 x^2-3 x y+y^2+x+2 y-8=0$Differentiating both sides with respect to $x$ using the chain rule and product rule:$\frac{d}{d x}(2 x^2) - \frac{d}{d x}(3 x y) + \frac{d}{d x}(y^2) + \frac{d}{d x}(x) + \frac{d}{d x}(2 y) - \frac{d}{d x}(8) = 0$$4 x - (3 y + 3 x \frac{d y}{d x}) + 2 y \frac{d y}{d x} + 1 + 2 \frac{d y}{d x} = 0$Grouping the terms containing $\frac{d y}{d x}$:$(2 y - 3 x + 2) \frac{d y}{d x} = 3 y - 4 x - 1$Therefore,$\frac{d y}{d x} = \frac{3 y - 4 x - 1}{2 y - 3 x + 2}$

If $2 x^2-3 x y+y^2+x+2 y-8=0$,then $\frac{d y}{d x}$ is equal to

Similar Questions

For $x \in R$,$f(x) = |\log 2 - \sin x|$ and $g(x) = f(f(x))$,then

If $2t = v^2$,then $\frac{dv}{dt}$ is equal to

If $y = \operatorname{Sin}^{-1}\left(\frac{4+5 \sin x}{5+4 \sin x}\right)$,then find $\frac{dy}{dx}$.

If $f(x)$ is a continuous and differentiable function satisfying $f(x) \cdot f(f(x)) = x^2 + 1$,$f(1) = 2$,and $f'(1) = k$,then the value of $f'(2)$ is

If $\tan y = \frac{x \sin \alpha}{1-x \cos \alpha}$ and $\frac{dy}{dx} = \frac{m}{x^2+2nx+1}$,then $m^2+n^2$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module