If $11 \%$ of the power of a $200 \ W$ bulb is converted to visible radiation,then the intensity of the light at a distance of $100 \ cm$ from the bulb is (in $W \ m^{-2}$)

Which of the following is a wrongly matched pair?

$A$ physical quantity $\vec{S}$ is defined as $\vec{S}=(\vec{E} \times \vec{B}) / \mu_0$,where $\vec{E}$ is the electric field,$\vec{B}$ is the magnetic field,and $\mu_0$ is the permeability of free space. The dimensions of $\vec{S}$ are the same as the dimensions of which of the following quantity(ies)?
$(A)$ $\frac{\text{Energy}}{\text{charge} \times \text{current}}$
$(B)$ $\frac{\text{Force}}{\text{Length} \times \text{Time}}$
$(C)$ $\frac{\text{Energy}}{\text{Volume}}$
$(D)$ $\frac{\text{Power}}{\text{Area}}$

For a $GPS$ navigation to track a mobile device,we use :-

In an electromagnetic wave,the electric field and magnetising field are $100\,V\,m^{-1}$ and $0.265\,A\,m^{-1}$ respectively. The maximum energy flow is.......$W\,m^{-2}$.

$A$ $100 \ W$ electric bulb produces electromagnetic radiation with an electric field amplitude of $2 \ V \ m^{-1}$ at a distance of $10 \ m$. Assuming it as a point source, estimate the efficiency of the bulb. (in $\%$)