If $\alpha$ and $\beta$ are the real roots of the equation $x^2+ax+b=0$,where $\alpha+\beta=\frac{1}{2}$ and $\alpha^3+\beta^3=\frac{37}{8}$,then find the value of $a-\frac{1}{b}$.

  • A
    $\frac{-1}{6}$
  • B
    $\frac{3}{2}$
  • C
    $\frac{-3}{2}$
  • D
    $\frac{1}{6}$

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