If 3 sisters and 8 other girls are together p | vedclass

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(D) Total number of girls $= 3 + 8 = 11$. Number of ways to arrange $11$ girls around a circle is $(11 - 1)! = 10!$. To find the number of ways where

Vedclass · Accepted Answer

$8 ! 	imes 84$

Vedclass · Answer

(D) Total number of girls $= 3 + 8 = 11$. Number of ways to arrange $11$ girls around a circle is $(11 - 1)! = 10!$. To find the number of ways where the $3$ sisters are $NOT$ seated together,we use the complement method: Total arrangements $-$ Arrangements where $3$ sisters are together. Treating the $3$ sisters as a single unit,we have $8 + 1 = 9$ units to arrange in a circle,which can be done in $(9 - 1)! = 8!$ ways. The $3$ sisters can be arranged among themselves in $3!$ ways. So,arrangements where $3$ sisters are together $= 8! 	imes 3!$. Required number of ways $= 10! - (8! 	imes 3!) = 10! - (8! 	imes 6)$. $= 8! 	imes (10 	imes 9 - 6) = 8! 	imes (90 - 6) = 8! 	imes 84$.

If $3$ sisters and $8$ other girls are together playing a game,then the number of ways in which all the girls are seated around a circle such that the three sisters are not seated together,is

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