If $\vec{\lambda}$ is a unit vector perpendicular to the plane of vectors $\vec{a}$ and $\vec{b}$,and the angle between them is $\theta$,then $\vec{a} \cdot \vec{b}$ will be:
- A$|\vec{a}| |\vec{b}| \sin \theta \vec{\lambda}$
- B$|\vec{a}| |\vec{b}| \cos \theta \vec{\lambda}$
- C$|\vec{a}| |\vec{b}| \cos \theta$
- D$|\vec{a}| |\vec{b}| \sin \theta$
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DifficultMHT CET 2026
View SolutionIf $\overrightarrow{a}, \overrightarrow{b}, \overrightarrow{c}$ are three vectors such that $\overrightarrow{a}=\overrightarrow{b}+\overrightarrow{c}$ and the angle between $\overrightarrow{b}$ and $\overrightarrow{c}$ is $\frac{\pi}{2}$, then:
If $\vec{a}$ and $\vec{b}$ are two vectors such that $|\vec{a}|=|\vec{b}|=\sqrt{2}$ and $\vec{a} \cdot \vec{b}=-1$,then the angle between $\vec{a}$ and $\vec{b}$ is
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