If a = 2i + j - k, b = i + 2j + k and c = i - | vedclass

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(C) The scalar triple product $a \cdot (b 	imes c)$ is given by the determinant of the components of vectors $a, b,$ and $c$: $a \cdot (b 	imes c) =

Vedclass · Accepted Answer

$12$

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(C) The scalar triple product $a \cdot (b 	imes c)$ is given by the determinant of the components of vectors $a, b,$ and $c$: $a \cdot (b 	imes c) = \begin{vmatrix} 2 & 1 & -1 \ 1 & 2 & 1 \ 1 & -1 & 2 \end{vmatrix}$ Expanding the determinant along the first row: $= 2(2 	imes 2 - 1 	imes (-1)) - 1(1 	imes 2 - 1 	imes 1) + (-1)(1 	imes (-1) - 1 	imes 2)$ $= 2(4 + 1) - 1(2 - 1) - 1(-1 - 2)$ $= 2(5) - 1(1) - 1(-3)$ $= 10 - 1 + 3 = 12$.

If $a = 2i + j - k, b = i + 2j + k$ and $c = i - j + 2k,$ then $a \cdot (b \times c) = $

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