If a=2 hat{i}+hat{j}-3 hat{k}, b=hat{i}-2 hat | vedclass

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(B) First, calculate the cross product $a 	imes b$: $a 	imes b = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \ 2 & 1 & -3 \ 1 & -2 & 3 \end{vmatri

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$8 \hat{i}-36 \hat{j}+60 \hat{k}$

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(B) First, calculate the cross product $a 	imes b$: $a 	imes b = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \ 2 & 1 & -3 \ 1 & -2 & 3 \end{vmatrix} = \hat{i}(3-6) - \hat{j}(6+3) + \hat{k}(-4-1) = -3 \hat{i} - 9 \hat{j} - 5 \hat{k}$. Next, calculate the cross product $c 	imes d$: $c 	imes d = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \ -1 & 1 & -4 \ 1 & 1 & 2 \end{vmatrix} = \hat{i}(2+4) - \hat{j}(-2+4) + \hat{k}(-1-1) = 6 \hat{i} - 2 \hat{j} - 2 \hat{k}$. Finally, calculate the cross product of the two resulting vectors: $(a 	imes b) 	imes (c 	imes d) = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \ -3 & -9 & -5 \ 6 & -2 & -2 \end{vmatrix} = \hat{i}(18-10) - \hat{j}(6+30) + \hat{k}(6+54) = 8 \hat{i} - 36 \hat{j} + 60 \hat{k}$.

If $a=2 \hat{i}+\hat{j}-3 \hat{k}$, $b=\hat{i}-2 \hat{j}+3 \hat{k}$, $c=-\hat{i}+\hat{j}-4 \hat{k}$ and $d=\hat{i}+\hat{j}+2 \hat{k}$, then $(a \times b) \times(c \times d)=$

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