If $a=2u+3v+7w$, $b=u+v-2w$ and $c=-u-2v-3w$, then $\left|\frac{[u, v, w]}{[a, b, c]}\right|(a+b+c) = $

  • A
    $12(u+v+w)$
  • B
    $3(u+v+w)$
  • C
    $\frac{2}{3}(u+v+w)$
  • D
    $\frac{1}{3}(u+v+w)$

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