If $\overrightarrow{a}=\hat{i}+\hat{j}+\hat{k}, \overrightarrow{b}=\hat{i}-\hat{j}+\hat{k}, \overrightarrow{c}=\hat{i}+\hat{j}-\hat{k}$ and $\overrightarrow{d}=\hat{i}-\hat{j}-\hat{k}$, then match the following List-$I$ with List-$II$:
List-$I$List-$II$
$(i)$ $\overrightarrow{a} \cdot \overrightarrow{b}$$(A)$ $\overrightarrow{a} \cdot \overrightarrow{d}$
(ii) $\overrightarrow{b} \cdot \overrightarrow{c}$$(B)$ $3$
(iii) $[\overrightarrow{a} \overrightarrow{b} \overrightarrow{c}]$$(C)$ $\overrightarrow{b} \cdot \overrightarrow{d}$
(iv) $\overrightarrow{b} \times \overrightarrow{c}$$(D)$ $2\hat{i}-2\hat{k}$
$(E)$ $2\hat{j}+2\hat{k}$
$(F)$ $4$

  • A
    $i-C, ii-A, iii-B, iv-F$
  • B
    $i-C, ii-A, iii-F, iv-E$
  • C
    $i-A, ii-C, iii-B, iv-F$
  • D
    $i-A, ii-C, iii-F, iv-D$

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