If $\bar{a}=\bar{i}-2\bar{j}+2\bar{k}$, $\bar{b}=6\bar{i}+3\bar{j}-2\bar{k}$, and $\bar{c}=-4\bar{i}+3\bar{j}+12\bar{k}$ are three vectors, then $\sqrt{(|\bar{a}|+|\bar{b}|+|\bar{c}|)+|\bar{a}+\bar{b}+\bar{c}|}=$

  • A
    $13$
  • B
    $13\sqrt{10}$
  • C
    $6$
  • D
    $10\sqrt{3}$

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