If V_0 is the volume of a standard unit cell | vedclass

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(C) The number of unit cells in volume $V$ is given by $\frac{V}{V_0}$.Since each unit cell contains $N_0$ atoms, the total number of atoms in volume

Vedclass · Accepted Answer

$M \frac{V}{V_0} \frac{N_0}{N_A}$

Vedclass · Answer

(C) The number of unit cells in volume $V$ is given by $\frac{V}{V_0}$.Since each unit cell contains $N_0$ atoms, the total number of atoms in volume $V$ is $\frac{V}{V_0} 	imes N_0$.The number of moles of germanium in volume $V$ is the total number of atoms divided by Avogadro's constant $N_A$, which is $\frac{V}{V_0} 	imes \frac{N_0}{N_A}$.The mass $m$ is the number of moles multiplied by the molar mass $M$.Therefore, $m = \frac{V}{V_0} 	imes \frac{N_0}{N_A} 	imes M$.

If $V_0$ is the volume of a standard unit cell of germanium crystal containing $N_0$ atoms, then the expression for the mass $m$ of a volume $V$ in terms of $V_0, N_0, M$ and $N_A$ is [here, $M$ is the molar mass of germanium and $N_A$ is the Avogadro's constant].

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