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(B) Given the equation $AB = 3I$, where $A$ and $B$ are square matrices of the same order and $I$ is the identity matrix.To find $A^{-1}$, we multiply

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$\frac{1}{3}B$

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(B) Given the equation $AB = 3I$, where $A$ and $B$ are square matrices of the same order and $I$ is the identity matrix.To find $A^{-1}$, we multiply both sides of the equation by $A^{-1}$ from the left:$A^{-1}(AB) = A^{-1}(3I)$Using the associative property of matrix multiplication, we get:$(A^{-1}A)B = 3(A^{-1}I)$Since $A^{-1}A = I$ and $A^{-1}I = A^{-1}$, the equation simplifies to:$IB = 3A^{-1}$$B = 3A^{-1}$Dividing both sides by $3$, we obtain:$A^{-1} = \frac{1}{3}B$

If $A$ and $B$ are square matrices of the same order and $AB = 3I$, then $A^{-1}$ is equal to

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