If $y = \tan^{-1} \left( \frac{4x}{1 + 5x^2} \right) + \tan^{-1} \left( \frac{2 + 3x}{3 - 2x} \right)$,then $\frac{dy}{dx} = $

  • A
    $\frac{1}{1 + 25x^2} + \frac{2}{1 + x^2}$
  • B
    $\frac{5}{1 + 25x^2} + \frac{2}{1 + x^2}$
  • C
    $\frac{5}{1 + 25x^2}$
  • D
    $\frac{1}{1 + 25x^2}$

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