If y = sec(x^{circ}),then frac{dy}{dx} = | vedclass

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Question

(C) Given that $y = \sec(x^{\circ})$.First,convert the angle from degrees to radians: $x^{\circ} = \frac{\pi x}{180} 	ext{ radians}$.So,$y = \sec\lef

Vedclass · Accepted Answer

$\frac{\pi}{180} \sec(x^{\circ}) 	an(x^{\circ})$

Vedclass · Answer

(C) Given that $y = \sec(x^{\circ})$.First,convert the angle from degrees to radians: $x^{\circ} = \frac{\pi x}{180} 	ext{ radians}$.So,$y = \sec\left(\frac{\pi x}{180}ight)$.Now,differentiate with respect to $x$ using the chain rule:$\frac{dy}{dx} = \frac{d}{dx} \left[ \sec\left(\frac{\pi x}{180}ight) ight]$$= \sec\left(\frac{\pi x}{180}ight) 	an\left(\frac{\pi x}{180}ight) \cdot \frac{d}{dx} \left( \frac{\pi x}{180} ight)$$= \sec(x^{\circ}) 	an(x^{\circ}) \cdot \frac{\pi}{180}$$= \frac{\pi}{180} \sec(x^{\circ}) 	an(x^{\circ})$.

If $y = \sec(x^{\circ})$,then $\frac{dy}{dx} = $

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