If $f(x) = \sin^{-1} \left( \frac{2x}{1 + x^2} \right)$, then $f' \left( \frac{1}{2} \right) =$
- A$\frac{8}{5}$
- B$\frac{5}{8}$
- C$\frac{4}{5}$
- D$0$
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