If 96500 C of electricity liberates one gram | vedclass

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(B) According to Faraday's law of electrolysis,the mass $m$ deposited is given by $m = \frac{E 	imes i 	imes t}{96500}$,where $E$ is the chemical eq

Vedclass · Accepted Answer

$6 \ 	ext{min} \ 42 \ 	ext{sec}$

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(B) According to Faraday's law of electrolysis,the mass $m$ deposited is given by $m = \frac{E 	imes i 	imes t}{96500}$,where $E$ is the chemical equivalent.Given: $m = 20 \ mg = 20 	imes 10^{-3} \ g$,$i = 0.15 \ A$,$E = 32$.Substituting the values: $20 	imes 10^{-3} = \frac{32 	imes 0.15 	imes t}{96500}$.$t = \frac{20 	imes 10^{-3} 	imes 96500}{32 	imes 0.15} = \frac{1930}{4.8} \approx 402.08 \ 	ext{sec}$.$402 \ 	ext{sec} = 6 \ 	ext{min} \ 42 \ 	ext{sec}$.

If $96500 \ C$ of electricity liberates one gram equivalent of any substance,the time taken for a current of $0.15 \ A$ to deposit $20 \ mg$ of copper from a solution of copper sulphate is (Chemical equivalent of copper = $32$).

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