If |a| = a and |b| = b,then left( frac{a}{a^2 | vedclass

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(C) Given that $|a| = a$ and $|b| = b$,this implies $a \ge 0$ and $b \ge 0$.We need to evaluate the expression $\left( \frac{a}{a^2} - \frac{b}{b^2} \

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$\left( \frac{a - b}{ab} \right)^2$

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(C) Given that $|a| = a$ and $|b| = b$,this implies $a \ge 0$ and $b \ge 0$.We need to evaluate the expression $\left( \frac{a}{a^2} - \frac{b}{b^2} \right)^2$.First,simplify the terms inside the parenthesis:$\frac{a}{a^2} = \frac{1}{a}$ and $\frac{b}{b^2} = \frac{1}{b}$.Substituting these into the expression,we get:$\left( \frac{1}{a} - \frac{1}{b} \right)^2 = \left( \frac{b - a}{ab} \right)^2$.Since $(b - a)^2 = (a - b)^2$,we have:$\left( \frac{a - b}{ab} \right)^2$.

If $|a| = a$ and $|b| = b$,then $\left( \frac{a}{a^2} - \frac{b}{b^2} \right)^2 = $

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