If {N_a} = {an : n in N},then the set {N_6} c | vedclass

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(C) Given that ${N_a} = \{an : n \in N\}$.This represents the set of all multiples of $a$.Therefore,${N_6} = \{6, 12, 18, 24, 30, 36, 42, 48, \dots\}$

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${N_{24}}$

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(C) Given that ${N_a} = \{an : n \in N\}$.This represents the set of all multiples of $a$.Therefore,${N_6} = \{6, 12, 18, 24, 30, 36, 42, 48, \dots\}$ and ${N_8} = \{8, 16, 24, 32, 40, 48, \dots\}$.The intersection ${N_6} \cap {N_8}$ consists of all numbers that are multiples of both $6$ and $8$.The common multiples of $6$ and $8$ are the multiples of their least common multiple,$LCM(6, 8)$.$LCM(6, 8) = 24$.Thus,${N_6} \cap {N_8} = \{24, 48, 72, \dots\} = {N_{24}}$.

If ${N_a} = \{an : n \in N\}$,then the set ${N_6} \cap {N_8} = $

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