If $\frac{x^3}{(2x - 1)(x + 2)(x - 3)} = p + \frac{q}{2x - 1} + \frac{r}{x + 2} + \frac{s}{x - 3}$,then:
- A$p = 1$
- B$p = 2$
- C$p = \frac{1}{2}$
- D$6q - 3r + 2s = 3$
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