If x g of a non-volatile,non-electrolytic so | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Raoult's Law for non-volatile solutes: $\frac{P^{	heta} - P}{P^{	heta}} = \frac{n_2}{n_1 + n_2}$.Given that the vapour pressure is

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(A) According to Raoult's Law for non-volatile solutes: $\frac{P^{	heta} - P}{P^{	heta}} = \frac{n_2}{n_1 + n_2}$.Given that the vapour pressure is reduced to $80 \%$ of the pure octane,$P = 0.8 P^{	heta}$,so $\frac{P^{	heta} - 0.8 P^{	heta}}{P^{	heta}} = 0.2$.For octane $(C_8H_{18})$,molar mass $M_1 = (8 	imes 12) + (18 	imes 1) = 114 \ g/mol$.Number of moles of octane $n_1 = \frac{114 \ g}{114 \ g/mol} = 1 \ mol$.Number of moles of solute $n_2 = \frac{x}{40}$.Substituting into the equation: $0.2 = \frac{n_2}{n_1 + n_2} = \frac{x/40}{1 + x/40}$.$0.2(1 + x/40) = x/40 \Rightarrow 0.2 + 0.2(x/40) = x/40$.$0.2 = 0.8(x/40) \Rightarrow 0.2 = x/50$.$x = 0.2 	imes 50 = 10 \ g$.

If $x \ g$ of a non-volatile,non-electrolytic solute is dissolved in $114 \ g$ of octane to reduce its vapour pressure to $80 \%$ of that of pure octane,then $x$ is ........... $g$. (Molar mass of solute $= 40 \ g/mol$)

Similar Questions

"Relative lowering in vapour pressure of a solution containing a non-volatile solute is directly proportional to the mole fraction of the solute". The above statement is:

The vapour pressure of pure liquid solvent is $0.50 \ atm$. When a non-volatile solute $B$ is added to the solvent,its vapour pressure drops to $0.30 \ atm$. The mole fraction of the solute $B$ is $......$

Which solution will show the maximum vapour pressure at $300 \ K$?

For a solution of volatile liquids,the partial vapour pressure of each component in the solution is directly proportional to:

The vapour pressure in $mm$ of $Hg$ of an aqueous solution obtained by adding $18 \ g$ of glucose $(C_6H_{12}O_6)$ to $180 \ g$ of water at $100^{\circ}C$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module