(C) In projectile motion,the velocity vector is always tangent to the trajectory path. At the maximum height,the vertical component of velocity $(v_y)

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its velocity makes zero angle with the horizontal at its maximum height

(C) In projectile motion,the velocity vector is always tangent to the trajectory path. At the maximum height,the vertical component of velocity $(v_y)$ becomes zero,while the horizontal component $(v_x = u \cos \theta)$ remains constant. Since the velocity vector only has a horizontal component at the maximum height,it makes an angle of $0^\circ$ with the horizontal. Therefore,option $C$ is correct.

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If a body is projected with an angle $\theta$ to the horizontal,then

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A
its velocity is always perpendicular to its acceleration
B
its velocity becomes zero at its maximum height
C
its velocity makes zero angle with the horizontal at its maximum height
D
the body just before hitting the ground,the direction of velocity coincides with the acceleration

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If a body is projected with an angle $\theta$ to the horizontal,then

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