If a brass bar is placed on a vibrating magne | vedclass

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(B) The time period of a vibrating magnet is given by the formula $T = 2\pi \sqrt{\frac{I}{MH}}$, where $I$ is the moment of inertia, $M$ is the magne

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(B) The time period of a vibrating magnet is given by the formula $T = 2\pi \sqrt{\frac{I}{MH}}$, where $I$ is the moment of inertia, $M$ is the magnetic moment, and $H$ is the horizontal component of the Earth's magnetic field.When a brass bar is placed on the vibrating magnet, the total moment of inertia $(I)$ of the system increases.Since the time period $T$ is directly proportional to the square root of the moment of inertia $(T \propto \sqrt{I})$, an increase in $I$ leads to an increase in the time period $T$.Therefore, the time period of the vibrating magnet increases.

If a brass bar is placed on a vibrating magnet, then its time period

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