(B) The degree of dissociation $\alpha = 0.75$ and for $AB$,the number of ions $n = 2$.The van't Hoff factor $i = 1 - \alpha + n\alpha = 1 - 0.75 + 2

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(B) The degree of dissociation $\alpha = 0.75$ and for $AB$,the number of ions $n = 2$.The van't Hoff factor $i = 1 - \alpha + n\alpha = 1 - 0.75 + 2 \times 0.75 = 1.75$.The elevation in boiling point is given by $\Delta T_{b} = i \times K_{b} \times m$.Substituting the values: $2.5 = 1.75 \times 0.52 \times m$.Calculating molality $m = \frac{2.5}{1.75 \times 0.52} = \frac{2.5}{0.91} \approx 2.747$.Rounding off to the nearest integer,we get $3$.

Class 12 Chemistry Solutions Colligative properties of electrolyte

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If a compound $AB$ dissociates to the extent of $75\,\%$ in an aqueous solution,the molality of the solution which shows a $2.5\, K$ rise in the boiling point of the solution is $......$ molal.
(Rounded-off to the nearest integer) $[K_{b} = 0.52\, K\, kg\, mol^{-1}]$

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A
$4$
B
$3$
C
$6$
D
$5$

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If a compound $AB$ dissociates to the extent of $75\,\%$ in an aqueous solution,the molality of the solution which shows a $2.5\, K$ rise in the boiling point of the solution is $......$ molal.(Rounded-off to the nearest integer) $[K_{b} = 0.52\, K\, kg\, mol^{-1}]$

Similar Questions

The boiling point of $0.001 \ M$ aqueous solutions of $NaCl$,$Na_{2}SO_{4}$,$K_{3}PO_{4}$ and $CH_{3}COOH$ should follow the order.

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If a compound $AB$ dissociates to the extent of $75\,\%$ in an aqueous solution,the molality of the solution which shows a $2.5\, K$ rise in the boiling point of the solution is $......$ molal.
(Rounded-off to the nearest integer) $[K_{b} = 0.52\, K\, kg\, mol^{-1}]$