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(B) To obtain a $1:1$ ratio of dominant to recessive phenotypes in the offspring,one parent must be heterozygous $(Aa)$ and the other must be homozygo

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$Aa \; \& \; aa$

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(B) To obtain a $1:1$ ratio of dominant to recessive phenotypes in the offspring,one parent must be heterozygous $(Aa)$ and the other must be homozygous recessive $(aa)$.This specific type of cross is known as a test cross.The Punnett square for the cross $Aa 	imes aa$ is as follows:- Gametes from $Aa$ parent: $A, a$- Gametes from $aa$ parent: $a, a$- Offspring genotypes: $Aa, Aa, aa, aa$- Phenotypic ratio: $50\;\%$ dominant $(Aa)$ and $50\;\%$ recessive $(aa)$.

If a cross between two individuals produces offspring with $50\;\%$ dominant character $(A)$ and $50\;\%$ recessive character $(a),$ then the genotypes of the parents are:

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