If a double-stranded DNA has 35 % Guanine,cal | vedclass

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(C) According to Chargaff's rule,in double-stranded $DNA$,the amount of Adenine $(A)$ is equal to Thymine $(T)$,and the amount of Guanine $(G)$ is equ

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$15$

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(C) According to Chargaff's rule,in double-stranded $DNA$,the amount of Adenine $(A)$ is equal to Thymine $(T)$,and the amount of Guanine $(G)$ is equal to Cytosine $(C)$.Given: $G = 35 \%$.Since $G = C$,therefore $C = 35 \%$.The sum of all four bases is $100 \%$,so $A + T + G + C = 100 \%$.Substituting the values: $A + T + 35 \% + 35 \% = 100 \%$.$A + T + 70 \% = 100 \%$.$A + T = 30 \%$.Since $A = T$,we can write $2T = 30 \%$.Therefore,$T = 15 \%$.

If a double-stranded $DNA$ has $35 \%$ Guanine,calculate the percent of Thymine in the $DNA$. (in $\%$)

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