If a hybrid text{DNA} (N^{15}N^{14}) is allow | vedclass

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(A) The replication of $	ext{DNA}$ is semi-conservative.Starting with one hybrid $	ext{DNA}$ molecule $(N^{15}N^{14})$:Generation $0$: $1$ hybrid $(

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$2$

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(A) The replication of $	ext{DNA}$ is semi-conservative.Starting with one hybrid $	ext{DNA}$ molecule $(N^{15}N^{14})$:Generation $0$: $1$ hybrid $(N^{15}N^{14})$.Generation $1$: The $N^{15}$ strand and $N^{14}$ strand separate. Each acts as a template for a new $N^{14}$ strand. Result: $2$ hybrid $	ext{DNA}$ $(N^{15}N^{14})$.Generation $2$: The $2$ hybrid molecules produce $2$ hybrid $(N^{15}N^{14})$ and $2$ light $(N^{14}N^{14})$ $	ext{DNA}$ molecules.Generation $3$: The $2$ hybrid molecules produce $2$ hybrid $(N^{15}N^{14})$ and $2$ light $(N^{14}N^{14})$ $	ext{DNA}$ molecules,while the $2$ light molecules produce $4$ light $(N^{14}N^{14})$ $	ext{DNA}$ molecules.Total $	ext{DNA}$ molecules after $3$ generations = $2^3 = 8$.Number of $	ext{DNA}$ molecules containing the original $N^{15}$ strand = $2$ (these are the $2$ hybrid molecules).

If a hybrid $\text{DNA}$ $(N^{15}N^{14})$ is allowed to replicate in an $N^{14}$ medium,after three generations,how many $\text{DNA}$ molecules will contain $N^{15}$?

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