If a proton is projected in a direction perpe | vedclass

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(B) The magnetic force on a charged particle is given by $F = q(v 	imes B) = qvB \sin 	heta$. For the proton,the velocity is perpendicular to the ma

Vedclass · Accepted Answer

Proton will move in a circle with constant speed and there will be no effect on the motion of electron.

Vedclass · Answer

(B) The magnetic force on a charged particle is given by $F = q(v 	imes B) = qvB \sin 	heta$. For the proton,the velocity is perpendicular to the magnetic field,so $	heta = 90^\circ$. The force $F = qvB \sin 90^\circ = qvB$ acts as a centripetal force,causing the proton to move in a circular path with constant speed. For the electron,the velocity is parallel to the magnetic field lines,so $	heta = 0^\circ$. The force $F = qvB \sin 0^\circ = 0$. Since no force acts on the electron,its motion remains unaffected (it continues to move in a straight line).

If a proton is projected in a direction perpendicular to a uniform magnetic field with velocity $v$ and an electron is projected along the lines of force,what will happen to the proton and electron?

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