If a solution of 10^{-6} M HCl is diluted 1 | vedclass

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(C) Initial concentration of $HCl = 10^{-6} \ M$. After diluting $100$ times,the new concentration of $HCl$ is $10^{-6} / 100 = 10^{-8} \ M$. Since th

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$6.96$

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(C) Initial concentration of $HCl = 10^{-6} \ M$. After diluting $100$ times,the new concentration of $HCl$ is $10^{-6} / 100 = 10^{-8} \ M$. Since the concentration is very low,we must consider the contribution of $H^{+}$ ions from water. Total $[H^{+}] = [H^{+}]_{HCl} + [H^{+}]_{H_2O} = 10^{-8} + 10^{-7} = 1.1 	imes 10^{-7} \ M$. $pH = -\log[H^{+}] = -\log(1.1 	imes 10^{-7}) = 7 - \log(1.1) \approx 7 - 0.04 = 6.96$.

If a solution of $10^{-6} \ M \ HCl$ is diluted $100$ times,the $pH$ of the solution is:

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