If a substance with a half-life of 3 days is | vedclass

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(C) The number of half-lives $(n)$ is calculated as: $n = \frac{	ext{Total time}}{	ext{Half-life}} = \frac{12 \ days}{3 \ days} = 4$. The remaining

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$1/16$

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(C) The number of half-lives $(n)$ is calculated as: $n = \frac{	ext{Total time}}{	ext{Half-life}} = \frac{12 \ days}{3 \ days} = 4$. The remaining amount of substance $(N)$ is given by the formula: $N = N_0 \left( \frac{1}{2} ight)^n$. Substituting the value of $n$: $\frac{N}{N_0} = \left( \frac{1}{2} ight)^4 = \frac{1}{16}$. Therefore,the fraction of the substance remaining is $1/16$.

If a substance with a half-life of $3 \ days$ is kept for $12 \ days$,what fraction of the substance remains?

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