If acetic acid is mixed with sodium acetate,then the ${H^{+}}$ ion concentration will be:

When $HCl$ gas is passed through a saturated solution of $BaCl_2$,a white precipitate is obtained. This is due to:

Pure $NaCl$ is prepared by passing $HCl$ gas through a saturated solution of common salt in water. The principle used is:

Test tubes $A$ and $B$ contain solutions of $NH_4Cl$ and $NaCl$ respectively. What happens if $Mg(OH)_2$ solution is added to both test tubes?

Assertion : Addition of $NH_4OH$ to an aqueous solution of $BaCl_2$ in the presence of $NH_4Cl$ (excess) precipitates $Ba(OH)_2$.
Reason : $Ba(OH)_2$ is insoluble in water.

The solubility product of $AgCl$ is $8 \times 10^{-6}$. Find its new solubility in the presence of $0.01 \ M \ NaCl$.